The D/L method sets revised targets in rain-interrupted limited-overs matches in accordance with the relative run scoring resources which are at the disposal of the two sides.
The team batting first are referred to as ‘Team 1’ and the team batting second are referred to as ‘Team 2’.
The terms ‘target’ and ‘revised target’ are reserved exclusively for the minimum score Team 2 need to win.
N is the number of overs per innings for the match as decided at the moment of delivery of the first ball of the match.
S is Team 1’s total score.
R1 is the resource percentage (relative to a full 50-over innings) available to Team 1.
R2 is the resource percentage (relative to a full 50-over innings) available to Team 2.
T is Team 2’s target score.
Reading the table:
The single table applies to all lengths of one-day matches from 50 overs-per-side . Thus when there are 50 overs still to be received and no wickets have been lost, the resource percentage available is 100%. A 40-over innings starts with a resource percentage of 89.3% relative to a 50 over innings. An innings shortened to 25-overs before it starts commences with a resource percentage of 66.5% relative to 50-over innings.
You can see the table by clicking the link below :
http://in.yimg.com/icccricket/pdfs/d-l_table.pdfFor example, suppose that after 20 out of 50 overs a team have lost 2 wickets. They have 30 overs left. From the table you will see that the resource percentage remaining is 67.3%.
Suppose now that there is an interruption in play and 10 overs are lost from the innings. When play can resume there are only 20 overs left but there are still, of course, 2 wickets down, and the table now tells us that the resource percentage remaining is 52.4%. Thus the shortening of the innings has caused the team to lose a resource percentage of 67.3 - 52.4 = 14.9%.
Having started with a resource percentage of 100% and lost 14.9%, then if they complete their innings with no further loss of overs, they will have had a resource percentage available for their innings of 100 - 14.9 = 85.1%.
Example 1 (Suspension during Team 1’s innings)
In a 50 over-per-innings match, Team 1 reaches 79/3 after 20 overs and then
there is a suspension in play. It is decided that 20 overs of the match should be
lost, 10 of these by each team. Team 1 resumes to reach a final total of 180 in its
revised allocation of 40 overs.
Number of overs per innings at the start of match, N = 50
Resource percentage available to Team 1 at start of innings = 100%
Resource percentage remaining at suspension (30 overs left, 3 wkts lost) = 62.3%
Resource percentage remaining at resumption (20 overs left, 3 wkts lost) = 50.6%
Resource percentage lost due to suspension = 62.3 – 50.6 = 11.7%
Resource percentage available to Team 1, R1 = 100 – 11.7 = 88.3%
Number of overs available to Team 2 at the start of its innings = 40
Resource percentage available (40 overs left, 0 wkt lost), R2 = 90.3%
R2 is greater than R1, i.e. Team 2 has more resource available than had Team 1,
so its target should be increased. S = 180
Team 2’s revised target is T = S + G50 x (R2 – R1)/100 + 1 = 180 + 225 x
(90.3 – 88.3)/100 + 1 = 185 (rounded down).
Example 2 (delay to start of Team 2’s innings)
In an English National League match (45 overs per innings), Team 1 scores 212
in its allocated 45 overs. Rain then causes Team 2’s response to be delayed and
it is decided that it should be shortened to 35 overs.
Number of overs at start of match, N = 45.
Resource percentage available to Team 1 at start of its innings (45 overs left,
0 wkt lost) = 95.0%.
The innings was not interrupted, so R1 = 95.0%
Number of overs available to Team 2 at start of its innings = 35
Resource percentage available to Team 2 at start of innings (35 overs left, 0 wkt
lost) R2 = 82.7%.
R2 is less than R1; S = 212
Team 2’s revised target is T
= S x R2/R1 + 1 = 212 x 82.7/95.0 + 1 = 185 (rounded down).
Example 3 (suspension during Team 2’s innings)
In an One Day International match (50 overs per innings), Team 1 has scored
250 from its allocation of 50 overs in an uninterrupted innings. Team 2 has
received 12 overs and has scored 40/1. Then play is suspended and 10 overs
are lost.
Number of overs at start of match, N = 50.
Team 1’s innings was uninterrupted, so its resource percentage available, R1 = 100%.
Resource percentage available to Team 2 at start of innings = 100% .
Resource percentage remaining at suspension (38 overs left, 1 wkt lost) = 82.0%.
Resource percentage remaining at resumption (28 overs left, 1 wkt lost) = 68.8%.
Resource percentage lost due to suspension = 82.0 – 68.8 = 13.2% .
Resource percentage available to Team 2, R2 = 100 – 13.2 = 86.8% .
R2 is less than R1; S = 250.
Team 2’s revised target is
T = S x R2/R1 + 1 = 250 x 86.8/100 + 1 = 218 , and it needs a further 178 runs
from 28 overs.